Question

4-{-12÷4+[4 (4÷2+12-2)-6]}=

Answer 1

$4-(-12\div 4+(4 (4\div 2+12-2)-6))=$

$4-(-3+(4 (4\div 2+12-2)-6))=$

$4-(-3+(4 (2+12-2)-6))=$

$4-(-3+(4\times 12-6))$

$4-(-3+(48-6))$

$4-(-3+42)$

$4-39$

$-35$

Solución: -35

!Espero te sirva¡

Answer 2

Respuesta:

Explicación paso a paso: