resolver las siguientes ecuaciones 1)2×+10=12 2)9×-1=107-3× 3)3×-7=17 4)10×-8=8× 5)2×+3=×-9 6) 5×+8=7×-32 7)45×=180+40× 8) 4×-2=×+10 9)2×+7-5×=8+×-12 10)7(3×+2)-5(4×-2)+1=4(×-2)+1

Respuestas

Respuesta dada por: Omega314
12
1)2×+10=12
2x = 12 - 10
2x = 2
x = 2 / 2 = 1

2)9×-1=107-3×
9x + 3x = 107 + 1
12x = 108
x = 108 / 12 = 9

3)3×-7=17
3x = 17 + 7
3x = 24
x = 24 / 3 = 8

4)10×-8=8×
10x - 8x = 8
2x = 8
x = 8 / 2 = 4

5)2×+3=×-9
2x - x = -9 - 3
x = -12

6) 5×+8=7×-32
5x - 7x = -32 - 8
-2x = -40
2x = 40
x = 40 / 2 = 20

7)45×=180+40×
45x - 40x = 180
5x = 180
x = 180 / 5 = 36

8) 4×-2=×+10
4x - x = 10 + 2
3x = 12
x = 12 / 3 = 4

9)2×+7-5×=8+×-12
2x - 5x - x = 8 - 12 - 7
-4x = -11
4x = 11
x = 11 / 4 = 2,75

10)7(3×+2)-5(4×-2)+1=4(×-2)+1
21x + 14 - 20x + 10 + 1 = 4x - 8 + 1
21x - 20x - 4x = -8 + 1 - 14 - 10 - 1
-3x = -32
3x = 32
x = 32 / 3 = 10,666...
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