Question

X
$x {}^{2} + 16x + 64 = 0$
$- x {}^{2} - x + 6 = 0$
$x { }^{2} - 10x + 25 = 0$
$y {}^{2} - y - 56 = 0$
$z {}^{2} - 4z = 96$

ayuda por favor

Answer 1

x² +16x+64 = 0 » (x+8)² =0 » (x+8)(x+8)=0 » x= -8

-x²-x + 6 =0 »» (-1) » x² +x-6 =0 » (x+3)(x-2)=0 » x=-3

x²-10x +25=0 » (x-5)(x-5) »» x=5

y²-y-56 =0 » (y-8)(y+7) =0 » y=8

z²-4z=96 » z²-4z-96=0 » (z-12)(z+8)=0 » x= 12