Question

Ayundeme porfa es una tarea

Answer 1

12.
Mm NH3 = 17 g/mol
        HCl = 36.45 g/mol
    Cs2O = 281.8 g/mol

1. calcular moles de cada componente: (n = masa/Mm)

n NH3 = 43 g/ 17 g/mol = 2.53 mol
n Cs2O =25 g / 281.8 g/mol = 0.089 mol
n HCl = 87 g/ 36.45 g/mol = 2.38 tg/mol

2. calcular moles totales:  n = nNH3 + n Cs2O + nHCl

n totales = 2.53 moles + 0.089 moles + 2.38 moles
n totales = 4.999 moles ≈ 5 moles

3. calcular fraccion molar de cada componente

X NH3 = 2.53 moles/5 moles = 0.506

XCs2O = 0.089 moles / 5 moles = 0.0178 moles

XHCl = 2.38 moles / 5 moles = 0.476

13.

Mm NH3 = 17 g/mol
         N2 =  28 g/mol

Fracción molar:
n totales = 1
moles NH3 = sustancia a
moles  N2 = sustancia b        entonces:

Xa =  na /nt   ;    Xb = nb /nt

ahora sustutuir:

moles NH3 = 0.17  x 1 =  mol =  0.17 mol (a)
moles N2 = 0.83 x 1 mol = 0.83 mol (b)

se debe calcular la masa de cada sustancia aplicando la fórmula:
 n = masa/Mm

mNH3 = nNH3 x Mm  (sustancia a)

mn2 = nN2 x Mm ( sustancia b)

donde m Total = mNH3 + mN2 ( masa solución)

se  calcula el % de cada sustancia aplicando la

 %m/m = masa soluto  x  100
               ``````````````````
                    m solc.

%m/m (a) =  ma (mNH3)   x  100
                    ``````````````````
                     masa total

%m/m (b) =  m b (mN2)   x  100
                    ```````````````
                     masa total