Question

2+3(r-7)-7r=4(r-2)+8

Answer 1

$2+3(r-7)-7r=4(r-2)+8 \\ \\ 2+3r-21-7r=4r-8+8 \\ \\ 2-21-4r=4r \\ \\ -19=4r+ 4r \\ \\ -19 = 8r \\ \\ \boxed{r = -\frac{19}{8} }$

$Verifiquemos \\ \\ 2+3(r-7)-7r=4(r-2)+8 \\ \\ 2+3((- \frac{19}{8})-7)-7(- \frac{19}{8}) =4((- \frac{19}{8})-2)+8 \\ \\ 2 + 3(- \frac{75}{8}) + \frac{133}{8} = 4 (- \frac{35}{8}) + 8 \\ \\ 2 -\frac{225}{8} + \frac{133}{8} = - \frac{140}{8} + 8 \\ \\ 2 - \frac{92}{8} = - \frac{140}{8} + 8 \\ \\ \frac{16}{8} - \frac{92}{8} = - \frac{140}{8} + \frac{64}{8} \\ \\ - \frac{76}{8} = - \frac{76}{8}\checkmark$

Significa que el valor de r es Verdadero!

Esperoq ue te sirva, salu2!!!!