A=(\frac{1}{2})^{-4}+(\frac{1}{3})^{-3} +(\frac{4}{5})^{-1} - ( \frac{2}{7})^{-2}

Respuestas

Respuesta dada por: PascualDavid
3
A=(\frac{1}{2})^{-4}+(\frac{1}{3})^{-3} +(\frac{4}{5})^{-1} - ( \frac{2}{7})^{-2}\\=2^4+3^3+ \frac{5}{4} - \frac{7^2}{2^2} =16+9+ \frac{5}{4} - \frac{49}{4}=\\ \frac{64}{4} + \frac{36}{4}+  \frac{5}{4} - \frac{49}{4}= \frac{56}{4} = 14

A = 14

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