Obtén la solución de estas ecuaciones de primer grado a)4x+1+3x-5=2 (x-2)+30 b)3(x+8)=6 (x-2)+24 c)3 (x+8)-(x-4)=12 d)2(4-x)+3 (4x+16)=3 e)6 (x+8)-2 (x-4)=24 f)6(x-2)=3 (x+8 )-24
Respuestas
Respuesta dada por:
4
a)
![4x + 1 + 3x - 5 = 2 \\ 4x + 3x = 2 - 1 + 5 \\ 7x = 1 + 5 \\ 7x = 6 \\ x = \frac{6}{7} 4x + 1 + 3x - 5 = 2 \\ 4x + 3x = 2 - 1 + 5 \\ 7x = 1 + 5 \\ 7x = 6 \\ x = \frac{6}{7}](https://tex.z-dn.net/?f=4x+%2B+1+%2B+3x+-+5+%3D+2+%5C%5C+4x++%2B+3x+%3D+2+-+1++%2B+5+%5C%5C+7x+%3D+1+%2B+5+%5C%5C+7x+%3D+6+%5C%5C+x+%3D++%5Cfrac%7B6%7D%7B7%7D+)
b)
![3(x + 8) = 6(x - 2) + 24 \\ 3x + 24 = 6x - 12 + 24 \\ 24 + 12 - 24 = 6x - 3x \\ 12 - 24 = 3x \\ - 12 = 3x \\ \frac{ - 12}{3} = x \\ - 4 = x 3(x + 8) = 6(x - 2) + 24 \\ 3x + 24 = 6x - 12 + 24 \\ 24 + 12 - 24 = 6x - 3x \\ 12 - 24 = 3x \\ - 12 = 3x \\ \frac{ - 12}{3} = x \\ - 4 = x](https://tex.z-dn.net/?f=3%28x+%2B+8%29+%3D+6%28x+-+2%29+%2B+24+%5C%5C+3x+%2B+24+%3D+6x+-+12+%2B+24+%5C%5C+24+%2B+12+-+24+%3D+6x+-+3x+%5C%5C+12+-+24+%3D+3x+%5C%5C++-+12+%3D+3x+%5C%5C++%5Cfrac%7B+-+12%7D%7B3%7D++%3D++x+%5C%5C++-+4+%3D+x)
![3(x + 8) - (x - 4) = 12 \\ 3x + 24 - x + 4 = 12 \\ 3x - x = 12 - 24 - 4 \\ 2x = - 12 - 4 \\ 2x = - 16 \\ x = \frac{ - 16}{2} \\ x = - 8 3(x + 8) - (x - 4) = 12 \\ 3x + 24 - x + 4 = 12 \\ 3x - x = 12 - 24 - 4 \\ 2x = - 12 - 4 \\ 2x = - 16 \\ x = \frac{ - 16}{2} \\ x = - 8](https://tex.z-dn.net/?f=3%28x+%2B+8%29+-+%28x+-+4%29+%3D+12+%5C%5C+3x+%2B+24+-+x+%2B+4+%3D+12+%5C%5C+3x+-+x+%3D+12+-+24+-+4+%5C%5C+2x+%3D++-+12+-+4+%5C%5C+2x+%3D++-+16+%5C%5C+x+%3D++%5Cfrac%7B+-+16%7D%7B2%7D++%5C%5C+x+%3D++-+8)
c)
d)
![2(4 - x) + 3(4x + 16) = 3 \\ 8 - 2x + 12x + 48 = 3 \\ - 2x + 12x = 3 - 8 - 48 \\ 10x = - 53 \\ x = \frac{ - 53}{10} \\ x = - 5.3 2(4 - x) + 3(4x + 16) = 3 \\ 8 - 2x + 12x + 48 = 3 \\ - 2x + 12x = 3 - 8 - 48 \\ 10x = - 53 \\ x = \frac{ - 53}{10} \\ x = - 5.3](https://tex.z-dn.net/?f=2%284+-+x%29+%2B+3%284x+%2B+16%29+%3D+3+%5C%5C+8+-+2x+%2B+12x+%2B+48+%3D+3+%5C%5C++-+2x+%2B+12x+%3D+3+-+8+-+48+%5C%5C+10x+%3D++-+53+%5C%5C+x+%3D++%5Cfrac%7B+-+53%7D%7B10%7D++%5C%5C+x+%3D++-+5.3)
b)
c)
d)
Respuesta dada por:
1
Respuesta:
a)
4x + 1 + 3x - 5 = 2 \\ 4x + 3x = 2 - 1 + 5 \\ 7x = 1 + 5 \\ 7x = 6 \\ x = \frac{6}{7}
b)
3(x + 8) = 6(x - 2) + 24 \\ 3x + 24 = 6x - 12 + 24 \\ 24 + 12 - 24 = 6x - 3x \\ 12 - 24 = 3x \\ - 12 = 3x \\ \frac{ - 12}{3} = x \\ - 4 = x
3(x + 8) - (x - 4) = 12 \\ 3x + 24 - x + 4 = 12 \\ 3x - x = 12 - 24 - 4 \\ 2x = - 12 - 4 \\ 2x = - 16 \\ x = \frac{ - 16}{2} \\ x = - 8
c)
d)
2(4 - x) + 3(4x + 16) = 3 \\ 8 - 2x + 12x + 48 = 3 \\ - 2x + 12x = 3 - 8 - 48 \\ 10x = - 53 \\ x = \frac{ - 53}{10} \\ x = - 5.3
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