Question

si x ala n =8 Reducir : 64x ala 2n +x ala -2n

Answer 1

Si $x^{n} =8$ , Reducir $64 x^{2n} + x^{-2n}$

$64 x^{2n} + x^{-2n}$

$64 ((x^{n})^{2}) + x^{-2n}$

$64 (8)^{2} + x^{-2n}$

$64 (64) + x^{-2n}$

$64 (64) + \frac{1}{x^{2n}}$

$64 (64) + \frac{1}{(x^{n})^{2}}$

$64 (64) + \frac{1}{(8)^{2}}$

$64 (64) + \frac{1}{64}$

$4096 + \frac{1}{64}$

$\frac{262145}{64}$