Question

Ayudenme a demostrar esta funcion porfa xdxdxd D:

Answer 1

$\frac{1-cos\alpha}{tan\alpha cos\alpha} = \frac{1-cos\alpha}{ sen\alpha} \cdot \frac{1+cos\alpha}{1+cos\alpha}= \frac{1-cos^2\alpha}{sen\alpha(1+ cos\alpha)}= \frac{sen^2\alpha}{sen\alpha(1+ cos\alpha)} = \frac{sen\alpha}{1+cos\alpha}$

Saludos!