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Respuesta dada por:
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Interpolar 6 medios aritmeticos es encontrar 6 numeros cuyos extremos de la progresion sean -1 y 3
Tenemos:
an = a1 + (n - 1) * r
an = Ultimo termino = 3
a1 = primer termino = -1
r = razon =?
n = numero de termino = 8
3 = -1 + (8 -1)*r
3 = -1 + 7r
3 +1 = 7r
4 = 7r
4/7 = r
La razon = 4/7
1er termino = -1
2do termino = -1 + 4/7 = (-7 +4)/7 = -3/7
3er trmino = -3/7 + 4/7 = 1/7
4to termino = 1/7 + 4/7 = 5/7
5to termino = 5/7 + 4/7 = 9/7
6to termino = 9/7 + 4/7 = 13/7
7to termino = 13/7 +4/7 = 17/7
8vo termino = 17/7 4/7 = 21/7 =3
La progresion aritmetica queda:
-1 . -3/7. 1/7.5/7.9/7.13/7.17/7.3
Tenemos:
an = a1 + (n - 1) * r
an = Ultimo termino = 3
a1 = primer termino = -1
r = razon =?
n = numero de termino = 8
3 = -1 + (8 -1)*r
3 = -1 + 7r
3 +1 = 7r
4 = 7r
4/7 = r
La razon = 4/7
1er termino = -1
2do termino = -1 + 4/7 = (-7 +4)/7 = -3/7
3er trmino = -3/7 + 4/7 = 1/7
4to termino = 1/7 + 4/7 = 5/7
5to termino = 5/7 + 4/7 = 9/7
6to termino = 9/7 + 4/7 = 13/7
7to termino = 13/7 +4/7 = 17/7
8vo termino = 17/7 4/7 = 21/7 =3
La progresion aritmetica queda:
-1 . -3/7. 1/7.5/7.9/7.13/7.17/7.3
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