Question

composición porcentual de AgNO3

Answer 1

CALCULAR masa molecular del AgNO3

Ag:  1 x 107.86 = 107.86 g/mol
  N:  1 x 14 = 14 g/mol
  O:  3 x 16 = 48 g/mol
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                Mm = 169.86 g/mol

2. calcular % de cada elemento

Ag

   169.86 g --- 100 %
   107.86 g ---     x

                x = 63.49 % Ag

Nitrógeno

169.86 g --- 100 %
      14  g ---     x

                x = 8.24 % N

Oxígeno

169.86 g --- 100 %
       48 g ---     x

                x = 28.25 % O