Question

si: a#b=(a^3-a^2)(b+b)
hallar (3#2)#1
SON OPERADORES MATEMÁTICOS


AYUDA PLISS NO SEAN MAlos

Answer 1

3#2= (3^3-3^2)(2+2) = (27-9)(4)=18×4=72
(3#2)#1 = 72#1 = (72^3-72^2)(1+1) = 72^2 × 71 × 2 = 736 128