Question

An ant crawls at a rate of 216 ft per minute.at this rate, how long does it take the ant to crawl a distance of 515 ft?enter your answer as a mixed number in simplest form in the box.

Answer 1

216 ft ⇒ 1 minute
515 ft ⇒ A minutes

A = 515*1/216
A = 515/216
515/216 = (432/216) + (83/216) = 2 + (83/216)

Answer:
2 83/216 minutes

Answer 2

Hi,

I don't have a good use of English so excuse me if I commit grammatical errors.

Ant Crawling Rate = $\frac{216ft}{m}$

Then you use the Speed equation to get the time that takes the ant to crawl the distance of 515ft

$v= \frac{d}{t}$

v = speed

d = distance travelled

t = time taken

Just replace data:

$(\frac{216ft}{m}) = \frac{515ft}{t}$

$t= \frac{515ft}{ \frac{216ft}{m} }$

$t= (\frac{515}{216} )m$

$t=2.38minutes$

This number expressed as a mixed number is:

$2.38= \frac{515}{216}=2 \frac{83}{216}$

Hope that I helped you.