Question

Composición centecimal fe3po4a

Answer 1

1. calcular Mm FePO4 (FOSFATO FÉRRICO)

Fe:  1 x 56 = 56 g/mol
  P:  1 x 31 = 31 g/mol
  O: 4 x 16 = 64 g/mol
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          Mm = 151 g/mol

% de hierro
 
 151 g ----- 100 %
   56 g -----     x
     x = 37.08 % Fe

% FÓSFORO

 151 g ----- 100 %
   31 g -----     x
     x = 20.53 % P

% de oxigeno

 151 g ----- 100 %
   64 g -----     x
     x = 42.38 % O

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fosfato ferroso:  Fe3(PO4)2

1. calcular Mm Fe3(PO4)2 (FOSFATO FERROSO)

Fe:  3 x 56 = 168 g/mol
  P:  2 x 31 = 62 g/mol
  O: 8 x 16 = 128 g/mol
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          Mm = 358  g/mol

% de hierro
 
  358 g ----- 100 %
  168 g -----     x

     x = 46.93 % Fe

% FÓSFORO

 358 g ----- 100 %
   62 g -----     x

     x = 17.32 % P

% de oxigeno

 358 g ----- 100 %
 128 g -----     x

     x = 35.75 % O