Respuestas
Respuesta dada por:
44
( Método de igualación)
2x+5y=-24
8x-3y=19
![2x +5y = -24
2x +5y = -24](https://tex.z-dn.net/?f=2x+%2B5y+%3D+-24%0A)
![y=\frac{-24-2x}{5}..........(1) y=\frac{-24-2x}{5}..........(1)](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-24-2x%7D%7B5%7D..........%281%29)
![8x-3y=19
8x-3y=19](https://tex.z-dn.net/?f=8x-3y%3D19%0A%0A%0A)
![\quad y=-\frac{19-8x}{3}..........(2) \quad y=-\frac{19-8x}{3}..........(2)](https://tex.z-dn.net/?f=%5Cquad+y%3D-%5Cfrac%7B19-8x%7D%7B3%7D..........%282%29)
Igualar (1) y (2)
![\frac{-24-2x}{5}=-\frac{19-8x}{3} \frac{-24-2x}{5}=-\frac{19-8x}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B-24-2x%7D%7B5%7D%3D-%5Cfrac%7B19-8x%7D%7B3%7D)
![\left(-24-2x\right)\cdot \:3=-5\left(19-8x\right) \left(-24-2x\right)\cdot \:3=-5\left(19-8x\right)](https://tex.z-dn.net/?f=%5Cleft%28-24-2x%5Cright%29%5Ccdot+%5C%3A3%3D-5%5Cleft%2819-8x%5Cright%29)
![-72-6x=-95+40x
-72-6x=-95+40x](https://tex.z-dn.net/?f=-72-6x%3D-95%2B40x%0A%0A)
![x=\frac{1}{2}\quad x=\frac{1}{2}\quad](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B2%7D%5Cquad+)
Hallar y :
![y=\frac{-24-2x}{5} y=\frac{-24-2x}{5}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-24-2x%7D%7B5%7D)
![y= \frac{-24-2\cdot \left(\frac{1}{2}\right)}{5} y= \frac{-24-2\cdot \left(\frac{1}{2}\right)}{5}](https://tex.z-dn.net/?f=y%3D+%5Cfrac%7B-24-2%5Ccdot+%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%5Cright%29%7D%7B5%7D)
![y=\frac{-24-1}{5} y=\frac{-24-1}{5}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-24-1%7D%7B5%7D)
![y = -5 y = -5](https://tex.z-dn.net/?f=y+%3D+-5)
2x+5y=-24
8x-3y=19
Igualar (1) y (2)
Hallar y :
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