Question

¿Cuántos moles de ácido clorhidrico reaccionan con 15g de hidróxido de aluminio?
Al (OH)3+3HCl= AlCl3+3H2O

Answer 1

                            Al(OH)3  +  3HCl  → AlCl3  +  3 H2O

Mm Al(OH)3 = 78 g/mol


moles HCl = 15 g Al(OH)3  x 1 mol Al(OH)3  x     3 mol HCl
                                              ````````````````````    ````````````````````
                                                  78 g Al(OH)3     1 mol Al(OH)3

moles HCl = 0.577