Question

Colaboren me porfa necesito ayuda es que no me da el resultado

Answer 1

$-2x^2+ \dfrac{11}{20}x+ \dfrac{1}{10} = 0 \\ \\ \\ x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a}\qquad a= -2\qquad b= \dfrac{11}{20} \qquad c= \dfrac{1}{10} \\ \\ \\ Reemplazamos \to x_{1\ y\ 2}= \dfrac{- \frac{11}{20}\pm \sqrt{( \frac{11}{20}^2)-4(-2)( \frac{1}{10})} }{2(-2)} \\ \\ \\ Resolvemos \to x_{1\ y\ 2}= \dfrac{- \frac{11}{20}\pm \sqrt{( \frac{121}{400})-4(- \frac{2}{10})} }{-4}$

$x_{1\ y\ 2}= \dfrac{- \frac{11}{20}\pm \sqrt{( \frac{121}{400})+ \frac{8}{10}} }{-4} \\ \\ \\ x_{1\ y\ 2}= \dfrac{- \frac{11}{20}\pm \sqrt{( \frac{441}{400})} }{-4} \\ \\ \\ x_{1\ y\ 2}= \dfrac{- \frac{11}{20}\pm \frac{21}{20} }{-4} \\ \\ \\ x_{1}= \dfrac{- \frac{11}{20}+ \frac{21}{20} }{-4} \to x_{1}= \dfrac{\frac{1}{2} }{-4} \to \boxed{x_{1}= - \dfrac{1 }{8} }\\ \\ \\ x_{2}= \dfrac{- \frac{11}{20}- \frac{21}{20} }{-4} \to x_{2}= \dfrac{-\frac{8}{5} }{-4} \to \boxed{x_{2}=\frac{2}{5}}$

Respuesta final es 

$x_{2}= \dfrac{- \frac{11}{20}- \frac{21}{20} }{-4} \to x_{2}= \dfrac{-\frac{8}{5} }{-4} \to \boxed{x_{2}= \dfrac{2 }{5}\to 0,40 }$



Espero que te sirva, salu2!!!!