Question

Que masa de magnesio se necesita para que reaccione con 12.27 g de nitrogeno?:
Mg+N2=Mg3N2

Answer 1

                       3Mg  +  N2  → Mg3N2

Mm Mg = 24.30 g/mol
       N2 = 28 g/mol

g Mg = 12.27 g N2  x  1 mol N2  x  3 mol Mg  x  24.30 g Mg
                                   ``````````````    ``````````````    ```````````````
                                      28 g N2      1 mol N2      1 mol Mg

g Mg = 31.95 g