Question

Alguien que me pueda explicar este problema, por favor!!, la fórmula ya está balanceada

Answer 1

1. Buscar la Mm Al = 27 g/mol
                       H2O = 18 g/mol
                    Al2O3 = 102 g/mol

g H2O =150 g Al2O3  x  1 mol  Al2O3  x  3 mol H2O   x  18 g H2O
                                        ``````````````````    `````````````````    ````````````````
                                         102 g Al2O3      1 mol Al2O3    1 mol H2O

g H2O = 79.41

2.

Mm Al(OH)3 = 78 g/mol

g Al2O3 = 500 g Al(OH)3 x 1 mol Al(OH)3 x 1 mol Al2O3 x  102 g Al2O3
                                            ````````````````````  `````````````````     ``````````````````
                                              78 g al(OH)3     2 mol Al(OH)3   1 mol Al2O3

g Al2O3 = 326.92