Respuestas
Respuesta dada por:
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Buenas, vamos a resolver ambos trinomios cuadrados, mediante la demostración de trinomio al cuadrado.
DEMOSTRACIÓN de TRINOMIO AL CUADRADO:
![(a+b+c)^{2} \\ \\ a+b=x \\ \\ (a+b+c)^{2} =(x+c)^{2} \\ \\ (x+c)^{2}= x^{2} +c^{2}+2xc =(a+b)^{2}+c^{2}+2(a+b)c \\ \\ (a+b)^{2}+c^{2}+2(a+b)c \\ \\ a^{2}+b^{2}+2ab+c^{2}+2(a+b)c \\ \\ a^{2}+b^{2}+c^{2}+ 2ab +2(a+b)c \\ \\ a^{2}+b^{2}+c^{2}+ 2ab +2ac+2bc \\ \\ a^{2}+b^{2}+c^{2}+2(ab+ac+bc) (a+b+c)^{2} \\ \\ a+b=x \\ \\ (a+b+c)^{2} =(x+c)^{2} \\ \\ (x+c)^{2}= x^{2} +c^{2}+2xc =(a+b)^{2}+c^{2}+2(a+b)c \\ \\ (a+b)^{2}+c^{2}+2(a+b)c \\ \\ a^{2}+b^{2}+2ab+c^{2}+2(a+b)c \\ \\ a^{2}+b^{2}+c^{2}+ 2ab +2(a+b)c \\ \\ a^{2}+b^{2}+c^{2}+ 2ab +2ac+2bc \\ \\ a^{2}+b^{2}+c^{2}+2(ab+ac+bc)](https://tex.z-dn.net/?f=%28a%2Bb%2Bc%29%5E%7B2%7D+%5C%5C++%5C%5C+a%2Bb%3Dx+%5C%5C++%5C%5C+%28a%2Bb%2Bc%29%5E%7B2%7D+%3D%28x%2Bc%29%5E%7B2%7D+%5C%5C++%5C%5C+%28x%2Bc%29%5E%7B2%7D%3D+x%5E%7B2%7D+%2Bc%5E%7B2%7D%2B2xc+%3D%28a%2Bb%29%5E%7B2%7D%2Bc%5E%7B2%7D%2B2%28a%2Bb%29c+%5C%5C++%5C%5C+%28a%2Bb%29%5E%7B2%7D%2Bc%5E%7B2%7D%2B2%28a%2Bb%29c++%5C%5C++%5C%5C+a%5E%7B2%7D%2Bb%5E%7B2%7D%2B2ab%2Bc%5E%7B2%7D%2B2%28a%2Bb%29c+%5C%5C++%5C%5C+a%5E%7B2%7D%2Bb%5E%7B2%7D%2Bc%5E%7B2%7D%2B+2ab+%2B2%28a%2Bb%29c+%5C%5C++%5C%5C+a%5E%7B2%7D%2Bb%5E%7B2%7D%2Bc%5E%7B2%7D%2B+2ab+%2B2ac%2B2bc++%5C%5C++%5C%5C+a%5E%7B2%7D%2Bb%5E%7B2%7D%2Bc%5E%7B2%7D%2B2%28ab%2Bac%2Bbc%29)
Ahora a reemplazar...
![(x+y+1)^{2}=x^{2}+y^{2}+1^{2}+2(xy+x(1)+y(1)) \\ \\ x^{2}+y^{2}+1+2(xy+x+y) (x+y+1)^{2}=x^{2}+y^{2}+1^{2}+2(xy+x(1)+y(1)) \\ \\ x^{2}+y^{2}+1+2(xy+x+y)](https://tex.z-dn.net/?f=%28x%2By%2B1%29%5E%7B2%7D%3Dx%5E%7B2%7D%2By%5E%7B2%7D%2B1%5E%7B2%7D%2B2%28xy%2Bx%281%29%2By%281%29%29+%5C%5C++%5C%5C+x%5E%7B2%7D%2By%5E%7B2%7D%2B1%2B2%28xy%2Bx%2By%29)
![(2x+y+3)^{2}=(2x)^{2}+y^{2}+3^{2}+2(2x(y)+2x(3)+y(3)) \\ \\ 4x^{2} +y^{2}+9+2(2xy+6x+3y) (2x+y+3)^{2}=(2x)^{2}+y^{2}+3^{2}+2(2x(y)+2x(3)+y(3)) \\ \\ 4x^{2} +y^{2}+9+2(2xy+6x+3y)](https://tex.z-dn.net/?f=%282x%2By%2B3%29%5E%7B2%7D%3D%282x%29%5E%7B2%7D%2By%5E%7B2%7D%2B3%5E%7B2%7D%2B2%282x%28y%29%2B2x%283%29%2By%283%29%29+%5C%5C++%5C%5C++4x%5E%7B2%7D+%2By%5E%7B2%7D%2B9%2B2%282xy%2B6x%2B3y%29)
Espero haberte ayudado ;)
DEMOSTRACIÓN de TRINOMIO AL CUADRADO:
Ahora a reemplazar...
Espero haberte ayudado ;)
yamileth284vas:
Muchas gracias
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