Question

una solucion de acido nitrico al 19% de concentracion tiene una d=1.11g/ml calcular la molaridad

Answer 1

Mm HNO3= 63 g/mol

mol/L = 1.11 g  x  1000 mL   x  1 mol  x  19 g
            ``````````   ```````````````   ``````````   ````````
             1 mL           1 L              63 g      100 g

mol/L = 3.35 molar