Question

AYUDA PLEASEEEE¡¡¡ Resuelve: 1.- 6x-5y = 8      -2x + 7y = 8
2.- 5x + 3y = 26      4x - 6y = 4
3.- 5x - 2y = 11       x + 3y = 9
4.- x + y = 28        x - 2y = -2

Answer 1

Resuelve:

1.- 6x-5y = 8      -2x + 7y = 8 

$6x - 5y = 8 6x = 8 +5y x = 8 +5y / 6 .........(1) -2x +7y = 8 2x - 7y = -8 2x = 7y -8 x = 7y - 8 /2...(2) (1) y(2) Igualar$
$\frac{8+5y}{\:6}=\frac{7y-8}{2}$
$\left(8+5y\right)\cdot \:2=\left(7y-8\right)\cdot \:6 16+10y=42y-48 10y=42y-64 -32y=-64 y= 2 Hallar x 6x - 5(2) = 8 6x -10 = 8 6x = 18 x = 3$


2.- 5x + 3y = 26      4x - 6y = 4 

$5x + 3y = 26 5x = 26 -3y x = 26 - 3y /5 .....(1) 4x - 6y = 4 4x = 4 + 6y x = 4 + 6y /4.....(2) Igualar : (1) y (2)$
$\frac{26-3y}{5}=\frac{4+6y}{4}$
$\left(26-3y\right)\cdot \:4=\left(4+6y\right)\cdot \:5 104-12y=20+30y -42y=-84 y= 2 Hallar x 5x + 3(2) = 26 5x +6 = 26 5x = 20 x = 4$


3.- 5x - 2y = 11       x + 3y = 9

$5x - 2 y = 11 5x = 11 + 2y x = 11 +2 y / 5 ....(1) x + 3y = 9 x = 9 -3y .........(2) Igualar (1) y (2)$

$\frac{11+2y}{5}=9-3y$

$11+17y=45 17y=34 y = 2 Hallar x 5x - 2(2) = 11 5x - 4 = 11 5x = 15 x = 3$

4.- x + y = 28        x - 2y = -2

$x + y = 28 x = 28 -y ........(1) x -2y = -2 x = 2y -2 ......(2) Igualar (1) y (2) 28-y\:=\:2y-2 -y=2y-30 -3y=-30 y = 10 Hallar x x + y = 28 x +10 = 28 x = 18$