Question

2 xxx + 1 = 17 ayuda me ayudan esas tres equis son x a la tercera potencia

Answer 1

     2x^3 + 1 = 17
     2x^3 + 1 - 17 = 0
     2x^3 - 16 = 0
dividiendo todo entre 2
       x^3 - 8 = 0   diferencia de cubos
ecuación de tercer grado: tiene 3 raices
factorizando
      (x - 2)(x +2x + 4) = 0
cada factor será nulo
          x - 2 = 0
                             x1 = 2
    (x + 2x + 4) = 0
          x = (- b +/- √D)/2a
                          D = b^2 - 4.a.c = 2^2 - 4(1)(4) = 4 - 16 = - 12
          x = (- 2 +/- √-12)/2 = (- 2 +/- 2√-3)/2 = - 1 +/- √3i
                             x2 = - 1 - √3i
                             x3 = - 1 + √3i
                                                          S = {-1-√3i, -1+√3i, 2}  respuesta

Answer 2

2x^3 + 1 = 17

2x^3 = 17 - 1

2x^3 = 16

x^3 = 8

x^3 = 2^3

x = 2

Espero que te sirva. :)