Question

Calculo Vectorial
Hallar (X,Y,Z) Si:

Answer 1

2)

 (4,y)=x(2,3)
 (4,y)=(2x,3x)
4=2x  
4/2=x
2=x

y=3x
y=3(2)
y=6


3)
(x,x+y)=(y-2,6)

x=y-2

x+y=6

Remmplazamos
x+y=6
(y-2)+ y =6
2y-2=6
2y=8
y=8/2
y=4

x=y-2
x=(4)-2
x=2

4)
(2,3,4)=x(1,1,1) + y(1,1,0) + z(1,0,0)
(2,3,4)=(x,x,x) + (y,y,0) + (z,0,0)
(2,3,4)=(x+y+z,x+y,x) 

4=x

3=x+y
3=4+y
3-4=y
-1=y

2=x+y+z
2=(4)+(-1)+z
2=3 +z
2-3=z
-1=z