Question

gente acabo de encontra la masa molecular de 2KMnO4 como resultado me dio R//196u.m.a .

1mol de 2KMnO4 =196g

quisiera saber si está bien , para alguien que tiene experiencia en este tipo de ejercicios , gracias.

Answer 1

Mm

K = 39 g/mol
Mn = 55 g/mol
O = 16 g/mol

1. calcula Mm 2KMnO4

K: 2 x 39 g/mol = 78 g/mol
Mn: 2 x 55 g/mol = 110 g/mol
 O: 8 x 16 = 128 g/mol
``````````````````````````````````````````
                 Mm = 316 g/mol

```````````````````````````````````````````````````````````
  K: 1 x 39 g/mol = 39 g/mol
Mn: 1 x 55 g/mol = 55 g/mol
  O: 4 x 16 = 64 g/mol
``````````````````````````````````````````
                 Mm = 158 g/mol

entonces 2 (KMnO4) = 2 ( 158 g/mol) = 316 g/mol