Respuestas
Respuesta dada por:
0
La ecuación tiene como solución a 9/4
Saludos
Saludos
Adjuntos:
![](https://es-static.z-dn.net/files/dda/62bd2d5bacaa8ae84c2aa29c97262369.png)
Anónimo:
La primera raíz es negativa √(x-2)
Respuesta dada por:
0
Hallar la solución de la siguiente ecuación con radicales .
√(x-2)-√x-2=0
![========================== ==========================](https://tex.z-dn.net/?f=%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D)
![\sqrt{x-2}- \sqrt{x-2} = 0 \\ \\ \sqrt{x-2}= \sqrt{x-2} \\ \\ ( \sqrt{x-2})^{2}=( \sqrt{x-2})^{2} \\ \\ x - 2 = x - 2 \\ \\ x - x = - 2 + 2 \\ \\ 0x = 0 \\ \\ \boxed{x=0} \sqrt{x-2}- \sqrt{x-2} = 0 \\ \\ \sqrt{x-2}= \sqrt{x-2} \\ \\ ( \sqrt{x-2})^{2}=( \sqrt{x-2})^{2} \\ \\ x - 2 = x - 2 \\ \\ x - x = - 2 + 2 \\ \\ 0x = 0 \\ \\ \boxed{x=0}](https://tex.z-dn.net/?f=+%5Csqrt%7Bx-2%7D-+%5Csqrt%7Bx-2%7D++%3D+0+%5C%5C+%5C%5C+++%5Csqrt%7Bx-2%7D%3D+%5Csqrt%7Bx-2%7D+%5C%5C+%5C%5C+%28+%5Csqrt%7Bx-2%7D%29%5E%7B2%7D%3D%28+%5Csqrt%7Bx-2%7D%29%5E%7B2%7D+%5C%5C+%5C%5C+x+-+2+%3D+x+-+2+%5C%5C+%5C%5C+x+-+x+%3D+-+2+%2B+2+%5C%5C+%5C%5C+0x+%3D+0+%5C%5C+%5C%5C+%5Cboxed%7Bx%3D0%7D+++)
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La otra forma .
![\sqrt{x-2} - \sqrt{x} - 2 = 0 \\ \\ \sqrt{x-2} = \sqrt{x} + 2 \\ \\ \text{Elevamos ambas expresiones al cuadrado para eliminar ra\'iz} \\ \\ ( \sqrt[\not{2}]{x-2})^{\not{2}} = ( \sqrt{x} + 2)^{2} \\ \\ Aplicando\ binomio\ al\ cuadrado. \\ \\ \boxed{(a + b)=a^{2}+2ab+ b^{2}} \\ \\ x - 2 = ( \sqrt[\not{2}]{x})^{\not{2}} + 2( \sqrt{x})(2) + (2)^{2} \\ \\ \not{x} - 2= \not{x} + 4 \sqrt{x} + 4 \\ \\ - 2 = 4 \sqrt{x} + 4 \\ \\ - 2 - 4 = 4\sqrt{x} \\ \\ \not{-6}=\not{4} \sqrt{x} \\ \\ - 3 = 2 \sqrt{x} \sqrt{x-2} - \sqrt{x} - 2 = 0 \\ \\ \sqrt{x-2} = \sqrt{x} + 2 \\ \\ \text{Elevamos ambas expresiones al cuadrado para eliminar ra\'iz} \\ \\ ( \sqrt[\not{2}]{x-2})^{\not{2}} = ( \sqrt{x} + 2)^{2} \\ \\ Aplicando\ binomio\ al\ cuadrado. \\ \\ \boxed{(a + b)=a^{2}+2ab+ b^{2}} \\ \\ x - 2 = ( \sqrt[\not{2}]{x})^{\not{2}} + 2( \sqrt{x})(2) + (2)^{2} \\ \\ \not{x} - 2= \not{x} + 4 \sqrt{x} + 4 \\ \\ - 2 = 4 \sqrt{x} + 4 \\ \\ - 2 - 4 = 4\sqrt{x} \\ \\ \not{-6}=\not{4} \sqrt{x} \\ \\ - 3 = 2 \sqrt{x}](https://tex.z-dn.net/?f=+%5Csqrt%7Bx-2%7D+-++%5Csqrt%7Bx%7D+-+2+%3D+0+%5C%5C+%5C%5C++%5Csqrt%7Bx-2%7D+%3D++%5Csqrt%7Bx%7D+%2B+2+%5C%5C+%5C%5C+%5Ctext%7BElevamos+ambas+expresiones+al+cuadrado+para+eliminar+ra%5C%27iz%7D+%5C%5C+%5C%5C+%28+%5Csqrt%5B%5Cnot%7B2%7D%5D%7Bx-2%7D%29%5E%7B%5Cnot%7B2%7D%7D+%3D+%28+%5Csqrt%7Bx%7D+%2B+2%29%5E%7B2%7D++%5C%5C+%5C%5C+Aplicando%5C+binomio%5C+al%5C+cuadrado.+%5C%5C+%5C%5C+%5Cboxed%7B%28a+%2B+b%29%3Da%5E%7B2%7D%2B2ab%2B+b%5E%7B2%7D%7D+%5C%5C+%5C%5C+x+-+2+%3D+%28+%5Csqrt%5B%5Cnot%7B2%7D%5D%7Bx%7D%29%5E%7B%5Cnot%7B2%7D%7D+%2B+2%28+%5Csqrt%7Bx%7D%29%282%29+%2B+%282%29%5E%7B2%7D+%5C%5C+%5C%5C+%5Cnot%7Bx%7D+-+2%3D+%5Cnot%7Bx%7D+%2B+4+%5Csqrt%7Bx%7D+%2B+4++%5C%5C+%5C%5C+-+2+%3D+4+%5Csqrt%7Bx%7D+%2B+4+%5C%5C+%5C%5C+-+2+-+4+%3D++4%5Csqrt%7Bx%7D+%5C%5C+%5C%5C+%5Cnot%7B-6%7D%3D%5Cnot%7B4%7D+%5Csqrt%7Bx%7D+%5C%5C+%5C%5C+-+3+%3D+2+%5Csqrt%7Bx%7D+)
![\left(- \dfrac{3}{2}\right)^{2} \ = (\sqrt{x})^{2} \\ \\ \\ \boxed{ \dfrac{9}{4} = x } \left(- \dfrac{3}{2}\right)^{2} \ = (\sqrt{x})^{2} \\ \\ \\ \boxed{ \dfrac{9}{4} = x }](https://tex.z-dn.net/?f=%5Cleft%28-+%5Cdfrac%7B3%7D%7B2%7D%5Cright%29%5E%7B2%7D+%5C%C2%A0%3D++%28%5Csqrt%7Bx%7D%29%5E%7B2%7D+%5C%5C+%5C%5C+%5C%5C+%5Cboxed%7B+%5Cdfrac%7B9%7D%7B4%7D++%3D+x+%7D)
√(x-2)-√x-2=0
La otra forma .
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