Respuestas
Respuesta dada por:
1
a) ácido sulfúrico: H2SO4
SO3 + H2O → H2SO4
Mm
H: 2 x 1 = 2 g/mol
S: 1 x 32 = 32 g/mol
O: 4 x 16 = 64 g/mol
````````````````````````````
Mm = 98 g/mol
b) hidróxido de sodio: NaOH
Mm
Na: 1 x 23 = 23 g/mol
O: 1 x 16 = 16 g/mol
H: 1 x 1 = 1 g/mol
```````````````````````````````
Mm = 40 g/mol
c) KCl fórmula del cloruro de potasio
Mm
K: 1 x 39 = 39 g/mol
Cl: 1 x 35.5 = 35.5 g/mol
``````````````````````````````````````
Mm = 74.5 g/mol
SO3 + H2O → H2SO4
Mm
H: 2 x 1 = 2 g/mol
S: 1 x 32 = 32 g/mol
O: 4 x 16 = 64 g/mol
````````````````````````````
Mm = 98 g/mol
b) hidróxido de sodio: NaOH
Mm
Na: 1 x 23 = 23 g/mol
O: 1 x 16 = 16 g/mol
H: 1 x 1 = 1 g/mol
```````````````````````````````
Mm = 40 g/mol
c) KCl fórmula del cloruro de potasio
Mm
K: 1 x 39 = 39 g/mol
Cl: 1 x 35.5 = 35.5 g/mol
``````````````````````````````````````
Mm = 74.5 g/mol
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