Question

(x-2)²+x(x-3)=3(x+4)(x-3)-(x+2)(x-1)+2 ayudenme

Answer 1

(x-2)²+x(x-3)=3(x+4)(x-3)-(x+2)(x-1)+2
(x-2)²+x²-3x=3(x²-3x+4x-12)-(x²-x+2x-2)+2
(x-2)²+x²-3x=3(x²+x-12)-(x²+x-2)+2
(x-2)²+x²-3x=3x²+3x-36-x²-x+2+2
(x-2)²+x²-3x=2x²+2x-32
(x-2)²=2x²+2x-32-x²+3x
(x-2)²=x²+5x-32
x²-4x+4=x²+5x-32
x²+5x-32-x²+4x-4=0
9x-36=0
Llegados a este punto incluso podemos ver cuanto vale x:
9x=36
x=36/9
x=4