Question

un volumen de 1.3 litros de un gas medido a 19 celsius y 0.97 atmosferas tiene una masa de 2.55grs.calcular masa molecular del gas

Answer 1

Aplicar Ley de los Gases Ideales

V x P = n x R x T

R = 0.082 (L atm / mol K)
T =19 ºC + 273 = 292 K
P = 0.97 atm
V = 1.3 L
n (moles) = ?

1.calcular n

n =           1.3 L  x  0.97 atm
     ``````````````````````````````````````````
        292 K x 0.082 (L atm / mol K)

n = 0.052 moles

2. calcular Mm

n = masa/Mm

Mm = 2.55 g / 0.052 mol

Mm = 49.04 g/mol