Necesito resolver un cuadro de ecuaciones de estado
Con estas formulas en esta debo hallar tempreratura;
Formula; T= pv/nR
Datos;
P=640mm hg
V=1500 cm
T= ?
N= 1mol
En esta debo hallar moles
Formula;
N=pv/Rt
Datos:
P=5atm
V= 2l
T=300 °c
N= ?
En esta volumen
Formula v= NRT/P
Datos;
P=1200torr
V=?
T= 25°c
N= 6
Ayudenme porfavor :( ♡
Respuestas
Respuesta dada por:
2
a) Hallar temperatura
T = ?
P = 640 mmHg/760 = 0.84 at
V = 1500 cm³ = 1500 mL / 1000 = 1.5 L
R = 0.0821 (L atm / mol K)
n = 1 mol
P x V = n x R x T
T = 0.84 atm x 1.5 L
`````````````````````````````````````
0.0821(L atm/mol K) x 1 mol
T = 15.35 K
b) Hallar moles
n = P x V
`````````
R x T
P = 5 atm
V = 2 L
T = 300 ºC + 273 = 573 K
R = 0.0821 (L atm / mol K)
n = 5 atm x 2 L
``````````````````````````````````````
0.0821(L atm/mol K) x 573K
n = 0.21 moles
c) V = ?
V = n x R x T
``````````````
P
n = 6 moles
R = 0.0821 (L atm/mol K)
T = 25 ºC + 273 = 298 K
P = 1200 Torr
1 torr ----- 0.001316 atmósferas
1200 torr ----- x
x = 1.58 atm
V = 6 moles x 0.0821 (L atm/mol K) x 298 K
```````````````````````````````````````````````````````
1.58 atm
V = 92.90 L
T = ?
P = 640 mmHg/760 = 0.84 at
V = 1500 cm³ = 1500 mL / 1000 = 1.5 L
R = 0.0821 (L atm / mol K)
n = 1 mol
P x V = n x R x T
T = 0.84 atm x 1.5 L
`````````````````````````````````````
0.0821(L atm/mol K) x 1 mol
T = 15.35 K
b) Hallar moles
n = P x V
`````````
R x T
P = 5 atm
V = 2 L
T = 300 ºC + 273 = 573 K
R = 0.0821 (L atm / mol K)
n = 5 atm x 2 L
``````````````````````````````````````
0.0821(L atm/mol K) x 573K
n = 0.21 moles
c) V = ?
V = n x R x T
``````````````
P
n = 6 moles
R = 0.0821 (L atm/mol K)
T = 25 ºC + 273 = 298 K
P = 1200 Torr
1 torr ----- 0.001316 atmósferas
1200 torr ----- x
x = 1.58 atm
V = 6 moles x 0.0821 (L atm/mol K) x 298 K
```````````````````````````````````````````````````````
1.58 atm
V = 92.90 L
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