Question

1. 27+3 -45/5+16=
2. (2.4+12) (6-4)=
3. 3.9+(6+5-3) -12:4=
4. 440-[30+6(19-12)]=
5. 2{4 [7+4(5.3-9)] -3 (40-8)}=
6. 7.3+[6+2(2/4+3.2)-7.4]+9/3=

Answer 1

$27 + 3 - \frac{45}{5} + 16 = \\ 27 + 3 - 7 + 16 = \\ 39$
$(2.4 + 12)(6 - 4) = \\ 24.4 \times 2 = \\ 48.8$
$3.9 + (6 + 5 - 3) - \frac{12}{4} = \\ 3.9 + 9 - 3 = \\ 9.9$
$440 - (30 + 6(19 - 12)) = \\ 440 - (30 + 6 \times 7) = \\ 440 - (30 + 42) = \\ 440 - 72 = \\ 368$
$2(4(7 + 4(5.3 - 9)) - 3(40 - 8) = \\ 8(7 + 4 ( - 3.7) - 3 \times 32) = \\ 8(7 - 14.8 - 96) = \\ 8( - 103.8) = \\ - 830.4$
$7.3 + (6 + 2( \frac{2}{4} + 3.2) - 7.4) + \frac{9}{3} = \\ 7.3 + (6 + 2(0.5 + 3.2) - 7.4) + 3 = \\ 7.3 + (6 + 2 \times 3.7) - 7.4 + 3 = \\ 7.3 + (6 + 7.4) - 7.4 + 3 = \\ 16.3$