Como lo hago con explicacion plis :
a)27 4/3=
b)81 3/4=
c(25) 1/2
d(216) -2/3
ojo las fraciones como 4/3 son como potencias
Respuestas
Respuesta dada por:
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▪A tomar en cuenta:
° Propiedades de potenciación:
![\boxed{ {a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} } } \boxed{ {a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} } }](https://tex.z-dn.net/?f=+%5Cboxed%7B+%7Ba%7D%5E%7B+%5Cfrac%7Bm%7D%7Bn%7D+%7D+%3D+%5Csqrt%5Bn%5D%7B+%7Ba%7D%5E%7Bm%7D+%7D+%7D)
![\boxed{ {a}^{b} \: ^{.} \: {a}^{c} = {a}^{b + c} } \boxed{ {a}^{b} \: ^{.} \: {a}^{c} = {a}^{b + c} }](https://tex.z-dn.net/?f=+%5Cboxed%7B+%7Ba%7D%5E%7Bb%7D+%5C%3A+%5E%7B.%7D+%5C%3A+%7Ba%7D%5E%7Bc%7D+%3D+%7Ba%7D%5E%7Bb+%2B+c%7D+%7D)
![\boxed{{a}^{ - b} = \frac{1}{ {a}^{b} } } \boxed{{a}^{ - b} = \frac{1}{ {a}^{b} } }](https://tex.z-dn.net/?f=+%5Cboxed%7B%7Ba%7D%5E%7B+-+b%7D+%3D+%5Cfrac%7B1%7D%7B+%7Ba%7D%5E%7Bb%7D+%7D+%7D)
▪Soluciones
![a). \\ \boxed{{27}^{ \frac{4}{3} }} = \\ \\ \sqrt[3]{ {27}^{4} } = \\ \\ \sqrt[3]{ {27}^{3} \: ^{.} \: {27}^{1} } = \\ \\ \sqrt[3]{ {27}^{3} \: ^{.} \: {3}^{3} } = \\ \\ 27 \:^{.} \: 3 = \\ \\ \boxed{\boxed{81}} a). \\ \boxed{{27}^{ \frac{4}{3} }} = \\ \\ \sqrt[3]{ {27}^{4} } = \\ \\ \sqrt[3]{ {27}^{3} \: ^{.} \: {27}^{1} } = \\ \\ \sqrt[3]{ {27}^{3} \: ^{.} \: {3}^{3} } = \\ \\ 27 \:^{.} \: 3 = \\ \\ \boxed{\boxed{81}}](https://tex.z-dn.net/?f=a%29.+%5C%5C+%5Cboxed%7B%7B27%7D%5E%7B+%5Cfrac%7B4%7D%7B3%7D+%7D%7D+%3D+%5C%5C+%5C%5C+%5Csqrt%5B3%5D%7B+%7B27%7D%5E%7B4%7D+%7D+%3D+%5C%5C+%5C%5C+%5Csqrt%5B3%5D%7B+%7B27%7D%5E%7B3%7D+%5C%3A+%5E%7B.%7D+%5C%3A+%7B27%7D%5E%7B1%7D+%7D+%3D+%5C%5C+%5C%5C+%5Csqrt%5B3%5D%7B+%7B27%7D%5E%7B3%7D+%5C%3A+%5E%7B.%7D+%5C%3A+%7B3%7D%5E%7B3%7D+%7D+%3D+%5C%5C+%5C%5C+27+%5C%3A%5E%7B.%7D+%5C%3A+3+%3D+%5C%5C+%5C%5C+%5Cboxed%7B%5Cboxed%7B81%7D%7D)
![b). \\ \boxed{{81}^{ \frac{3}{4} }} = \\ \\ \sqrt[4]{ {81}^{3} } = \\ \\ \sqrt[4]{ {81}^{1} \: ^{.} \: {81}^{1} \: ^{.} \: {81}^{1} } = \\ \\ \sqrt[4]{ {3}^{4} \: ^{.} \: {3}^{4} \: ^{.} \: {3}^{4} } = \\ \\ 3 \: ^{.} \: 3 \: ^{.} \: 3 = \\ \\ \boxed{\boxed{27}} b). \\ \boxed{{81}^{ \frac{3}{4} }} = \\ \\ \sqrt[4]{ {81}^{3} } = \\ \\ \sqrt[4]{ {81}^{1} \: ^{.} \: {81}^{1} \: ^{.} \: {81}^{1} } = \\ \\ \sqrt[4]{ {3}^{4} \: ^{.} \: {3}^{4} \: ^{.} \: {3}^{4} } = \\ \\ 3 \: ^{.} \: 3 \: ^{.} \: 3 = \\ \\ \boxed{\boxed{27}}](https://tex.z-dn.net/?f=b%29.+%5C%5C+%5Cboxed%7B%7B81%7D%5E%7B+%5Cfrac%7B3%7D%7B4%7D+%7D%7D+%3D+%5C%5C+%5C%5C+%5Csqrt%5B4%5D%7B+%7B81%7D%5E%7B3%7D+%7D+%3D+%5C%5C+%5C%5C+%5Csqrt%5B4%5D%7B+%7B81%7D%5E%7B1%7D+%5C%3A+%5E%7B.%7D+%5C%3A+%7B81%7D%5E%7B1%7D+%5C%3A+%5E%7B.%7D+%5C%3A+%7B81%7D%5E%7B1%7D+%7D+%3D+%5C%5C+%5C%5C+%5Csqrt%5B4%5D%7B+%7B3%7D%5E%7B4%7D+%5C%3A+%5E%7B.%7D+%5C%3A+%7B3%7D%5E%7B4%7D+%5C%3A+%5E%7B.%7D+%5C%3A+%7B3%7D%5E%7B4%7D+%7D+%3D+%5C%5C+%5C%5C+3+%5C%3A+%5E%7B.%7D+%5C%3A+3+%5C%3A+%5E%7B.%7D+%5C%3A+3+%3D+%5C%5C+%5C%5C+%5Cboxed%7B%5Cboxed%7B27%7D%7D)
![c). \\ \boxed{{25}^{ \frac{1}{2} } } = \\ \\ \sqrt[2]{ {25}^{1} } = \\ \\ \sqrt[2]{ {5}^{2} } = \\ \\ \boxed{\boxed{5}} c). \\ \boxed{{25}^{ \frac{1}{2} } } = \\ \\ \sqrt[2]{ {25}^{1} } = \\ \\ \sqrt[2]{ {5}^{2} } = \\ \\ \boxed{\boxed{5}}](https://tex.z-dn.net/?f=c%29.+%5C%5C+%5Cboxed%7B%7B25%7D%5E%7B+%5Cfrac%7B1%7D%7B2%7D+%7D+%7D+%3D+%5C%5C+%5C%5C+%5Csqrt%5B2%5D%7B+%7B25%7D%5E%7B1%7D+%7D+%3D+%5C%5C+%5C%5C+%5Csqrt%5B2%5D%7B+%7B5%7D%5E%7B2%7D+%7D+%3D+%5C%5C+%5C%5C+%5Cboxed%7B%5Cboxed%7B5%7D%7D)
° Propiedades de potenciación:
▪Soluciones
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