Question

Resolver la ecuación exponencial 2^(x+1)=8

Answer 1

Resolver la ecuación exponencial 2^(x+1)=8

$2^{x+1}=8 \\ \\ 2^{x+1}= 2^{3} \ \ \ \ ==\ \textgreater \ Descompongo \ \ el \ \ 8 \\ \\ x+1=3 \ \ \ \ ==\ \textgreater \ Igualo \\ \\ x=3-1 \ \ \ \ Despejo \ \ x \\ \\ \boxed{x=2}$




$' \odot \odot\\ \overbrace{100pre} \\ \underbrace{Salu2}$

Answer 2

Respuesta:

2^(x+1)=8

\begin{gathered} 2^{x+1}=8 \\ \\ 2^{x+1}= 2^{3} \ \ \ \ ==\ \textgreater \ Descompongo \ \ el \ \ 8 \\ \\ x+1=3 \ \ \ \ ==\ \textgreater \ Igualo \\ \\ x=3-1 \ \ \ \ Despejo \ \ x \\ \\ \boxed{x=2}\end{gathered}

2

x+1

=8

2

x+1

=2

3

== \textgreater Descompongo el 8

x+1=3 == \textgreater Igualo

x=3−1 Despejo x

x=2

\begin{gathered}' \odot \odot\\ \overbrace{100pre} \\ \underbrace{Salu2}\end{gathered}

′

⊙⊙

100pre

Salu2