Question

Porfavor ayudenmen!! Me urge

Answer 1

$a) \dfrac{1}{2}x + \dfrac{3}{4}+ \dfrac{6}{5}x+ \dfrac{1}{2}- \dfrac{5}{10} = \\ \\ \\ \dfrac{1}{2}x + \dfrac{6}{5}x+ \dfrac{3}{4}+ \dfrac{1}{2}- \dfrac{5}{10} = \qquad juntamos \ los \ semejantes\ y \ resolvemos \\ \\ \\ \left(\dfrac{1*5}{2*5}x + \dfrac{6*2}{5*2}x\right)+\left( \dfrac{3*5}{4*5}+ \dfrac{1*10}{2*10}- \dfrac{5*2}{10*2}\right) = \\ \\ \\ \left(\dfrac{5}{10}x + \dfrac{12}{10}x\right)+\left( \dfrac{15}{20}+ \dfrac{10}{20}- \dfrac{10}{20}\right) =$

$\left(\dfrac{5+12}{10}x \right)+\left( \dfrac{15+10-10}{20}\right) = \dfrac{17}{10}x+ \dfrac{15}{20}= \boxed{\dfrac{17}{10}x+ \dfrac{3}{4}}$


$b) a^2-7a^2-8a+6a-4a^2-6a^2-8a= \\ \\ (a^2-7a^2-4a^2-6a^2)+( -8a+6a-8a)= \\ \\ (-16a^2)+( -10a)= \boxed{-16a^2-10a}$


$c) 5x+2x-6x-4-5-2+8x= \\ \\ (5x+2x-6x+8x) +(-4-5-2)= \\ \\ (9x)+(-11)= \boxed{9x-11}$

$d) \dfrac{1}{2}+ \dfrac{3}{4}- \dfrac{5}{3}= \\ \\ \\ \dfrac{1*6}{2*6}+ \dfrac{3*3}{4*3}- \dfrac{5*4}{3*4}= \\ \\ \\ \dfrac{6}{12}+ \dfrac{9}{12}- \dfrac{20}{12}=\dfrac{6+9-20}{12}= \boxed{- \dfrac{5}{12} }$


$e) \dfrac{1}{3}* \dfrac{8}{4}= \dfrac{1*8}{3*4}= \dfrac{\not 8^2}{\not 1\not 2^3}= \boxed{\dfrac{2}{3}}$


$f) \dfrac{6}{3}: \dfrac{8}{2}= \dfrac{6*2}{3*8}= \dfrac{\not 1\not 2^1}{\not 2\not 4^2}= \boxed{ \dfrac{1}{2}}$

Espero que te sirva, salu2!!!!