Question

 3aX2-3a =



3x2-3x-6=



A3-a2-a+1 =

Answer 1

$Factoreo$

$3ax^2 -3a = 3a(x^2-1)= 3a (x-1)(x+1) \\ \\ 3x^2-3x -6= 3(x^2 - x - 2) =3(x-2)(x+1)$

$a^3 - a^2 -a +1 = a^2(a-1)-1(a-1)= (a^2-1)(a-1) =$$(a-1)(a+1)(a-1)$

Espero que te sirva, salu2!!!!