Question

se tratan 200 g de carbonato de calcio con una disolucion 4m de hcl , !

Answer 1

          CaCO3 + 2HCl → CaCl2 + CO2  +  H2O

Mm CaCO3 = 100 g/mol
             HCl = 35.5 g/mol

1. calcular g de HCl

g HCl = 200 g CaCO3  x  1 mol CaCO3  x  2 mol HCl  x   36.5 g HCl
                                        ````````````````````    ```````````````   `````````````````
                                         100 g CaCO3     1 mol CaCO3   1 mol HCl

g HCl = 146

2. calcular moles de HCl

n = masa/Mm

n = 146 g / 36.5 g/mol

n = 4 moles HCl

3. calcular volumen de la solución

M = n/V

V =  4 moles / 4 mol/L

V = 1 L de solución.

4. calcular moles de CO2

n = 200 g CaCO3 x 1 mol CaCO3  x 1 mol CO2
                                ```````````````````    ```````````````
                                 100 g CaCO3     1 mol CaCO3

n = 2 moles CO2