Question

encontrar la solución a estas equaciones:
a) 2x - 10 3(x - 12)
------------ - --------------- = -1
3 4

b) -3x - 3
------------- = 3 - 4(x + 2)
5

Answer 1

$\frac{2x-10}{3}- \frac{3(x-12)}{4}= -1 \\ \\ \frac{4(2x-10)}{(4)3}- \frac{(3)(3)(x-12)}{3(4)}=-1 \\ \\ \frac{8x-40}{12}- \frac{9x-108}{12}=-1 \\ \\ 8x-9x+108-40=-1(12) \\ \\ -x+68=-12 \\ \\ -x=-12-68 \\ \\ -x=-80 \\ \\ x=80 \\ .................................. \\ \\ \frac{-3x-3}{5}=3-4(x+2) \\ \\ \frac{-3x-3}{5}=3-4x-8 \\ \\ \frac{-3x-3}{5}=3-8-4x \\ \\ \frac{-3x-3}{5}=-5-4x \\ \\ -3x-3=5(-5-4x) \\ \\ -3x-3=-25-20x \\ \\ -3x+20x=-25+3 \\ \\ 17x=-22 \\ \\ x=- \frac{22}{17}$

Answer 2

$\frac{2x-10}{3}- \frac{3(x-12)}{4} = -1 \\ \\ \frac{4(2x-10)}{12}- \frac{3(3x-36)}{12} = -1 \\ \\\frac{(8x-40)}{12}- \frac{(9x-108)}{12} = -1 \\ \\ \frac{(8x-40)-(9x-108)}{12}= - 1 \\ \\ (8x-40)-(9x-108) = (-1)*12 \\ \\ 8x -9x -40+108= -12 \\ \\ -x + 68= -12 \\ \\ -x = -12-68 \\ \\ -x = -80 \\ \\ \boxed{x= 80}$

$\frac{-3x-3}{5} = 3 -4(x+2) \\ \\ -3x-3 = 5*(3-4(x+2)) \\ \\ -3x-3= 5*(3- 4x - 8 ) \\ \\ -3x-3= 5*(- 4x - 5 ) \\ \\ -3x-3= -20x - 25 \\ \\ -3x+20x= -25 + 3 \\ \\ 17x = -22 \\ \\ \boxed{x=\frac{-22}{17} }$

Espero que te sirva, salu2!!!!