Question

metodo determinante de x+y=12 x-y=8

Answer 1

x+y=12
x-y=8

determinate del sistema:
$det(s)= \left[\begin{array}{cc}1&1\\1&-1\end{array}\right]$
det(s)= -1-1=-2

determinate de la variable x:
$det(x)= \left[\begin{array}{cc}12&1\\8&-1\end{array}\right]$
det(x)=-12-8=-20

determinante de la variable y:
$det(s)= \left[\begin{array}{cc}1&12\\1&8\end{array}\right]$
det(y)=8-12=-4

x=det(x)/det(s)
y=det(y)/det(s)

Reemplazando:

x=-20/(-2)=10
y=-4/(-2)=2

Respuesta: x=10, y=2

Answer 2

ESTÁ BIEN EL OTR@ CHAB@ (: