Question

Porfa me resuelven estas dos operaciones de fracciones algebraicas?, gracias

$\frac{3x}{5x^{2} } \times \frac{ - 6x^{2} }{x} =$


$\frac{9y ^{2} }{2y} \times \frac{ - 3y}{4y^{3} } =$

Answer 1

Hola.

$\mathsf{\dfrac{3x}{5x^{2}}\times\dfrac{-6x^{2}}{x}=}\\\\\\ \mathsf{\dfrac{3x\times(-6x^2)}{5x^{2}\times x}=}\\\\\\ \mathsf{\dfrac{-18x^3}{5x^{3}}=}\\\\\\ \mathsf{\dfrac{-18\times x^3}{5\times x^{3}}=}\\\\\\ \mathsf{\dfrac{-18\times\diagup\!\!\!\!x^3}{5\times\diagup\!\!\!\!x^{3}}=}\\\\\\ \boxed{\mathsf{\dfrac{-18}{5}=3,6}}$
$\mathsf{\dfrac{9y^{2}}{2y}\times\dfrac{-3y}{4y^{3}}=}\\\\\\ \mathsf{\dfrac{9y^{2}\times(-3y)}{2y\times4y^3}=}\\\\\\ \mathsf{\dfrac{-27y^{3}}{8y^4}=}\\\\\\ \mathsf{\dfrac{-27\times y^{3}}{8y\times y^3}=}\\\\\\ \mathsf{\dfrac{-27\times\diagup\!\!\!\!y^{3}}{8y\times\diagup\!\!\!\!y^3}=}\\\\\\ \boxed{\mathsf{\dfrac{-27}{8y}}}$

Buenos estudios.