Respuestas
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20 ejemplos de binomios cúbicos.
1.- (a + 3)³= a³ + 3(a)²(3) + 3(a)(3)² + (3)³= 27 + 9a² + 27a + 27
2.- (p – q)³ = p³ – 3(p)²(q) + 3(p)(q)² – q³= p³ – 3p²q + 3pq² - q³
3.- (x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8
4.- (a – 3)³ = a³ + 3(a)²(3) + 3(a)(3)²+ (3)³= a³ + 9a² + 27a + 27
5.- (t + 4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³ == t³ + 3(t)²(4) + 3(t)(4)² + (4)³= t³ + 12t² + 48t + 64.
6.- (5a - 6)³ = (5a)³ - 3(5a)²(6) + 3(5a)(6)² - (6)³= 125a³ - 450a² + 540a - 216
7.- (2a - 1)³ = (2a)³ - 3(2a)²(1) + 3(2a)(1)² - (1)³ = 8a³ - 12a² + 6a - 1
8.- (2m-5)³= (2m)³+3(2m)²(-5)+3(2m)(-5)²+(-5)³= 8m³-60m²+150m+125
9.-(2x+y)³= (2x)³+3(2x)²(y)+3(2x)(y)²+(y)³= 8x³+12x²y+6xy²+y³
10.-(10+a)³= (10)³+3(10)²(a)+3(10)(a)²+(a)³= 1000+300a+30a²+a³
11.-(ab²-d⁵)³= (ab²)³+3(ab²)²(-d⁵)+3(ab²)(-d⁵)²+(d⁵)³ = a³b⁶ - 3a²b⁴d⁵ + 3ab²d¹⁰ + d¹⁵
12.- (10ab-3xy)³= (10ab)³+3(10ab)²(-3xy)+3(10ab)(-3xy)²+(-3xy)³=
1000a³b³ - 900a²b²xy+270abx²y²-27x³y³
13.- (t + 4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³= t³ + 12t² + 48t + 64
14.- (2a – b)³ = (2a)³ -3(2a)²(b)+3(2a)(b)²- b³ =8a³ – 3(4a²)b + 6ab² – b³= 8a³ – 12a²b + 6ab² – b³
15.- (x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8
16.-(1 – 3y)³ = (1)³ – 3(1)²(3y)+3(1)(3y)²- (3y)³ = 1 – 9y + 27y² - 27y³
17.- (2 – a)³ = 2³ – 3(2)²(a) + 3(2)(a)² – a³= 8 – 12a + 6a² - a³
18.- (x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8
19.- (a + 3)³= a³ + 3(a)²(3) + 3(a)(3)² + (3)³= 27 + 9a² + 27a + 27
20.- (3a - 5b)³ = (3a)³-3(3a)²(5b)+3(3a)(5b)²-(5b)³= 27a³ - 135a²b + 225ab² - 125b³
saludos!!!
1.- (a + 3)³= a³ + 3(a)²(3) + 3(a)(3)² + (3)³= 27 + 9a² + 27a + 27
2.- (p – q)³ = p³ – 3(p)²(q) + 3(p)(q)² – q³= p³ – 3p²q + 3pq² - q³
3.- (x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8
4.- (a – 3)³ = a³ + 3(a)²(3) + 3(a)(3)²+ (3)³= a³ + 9a² + 27a + 27
5.- (t + 4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³ == t³ + 3(t)²(4) + 3(t)(4)² + (4)³= t³ + 12t² + 48t + 64.
6.- (5a - 6)³ = (5a)³ - 3(5a)²(6) + 3(5a)(6)² - (6)³= 125a³ - 450a² + 540a - 216
7.- (2a - 1)³ = (2a)³ - 3(2a)²(1) + 3(2a)(1)² - (1)³ = 8a³ - 12a² + 6a - 1
8.- (2m-5)³= (2m)³+3(2m)²(-5)+3(2m)(-5)²+(-5)³= 8m³-60m²+150m+125
9.-(2x+y)³= (2x)³+3(2x)²(y)+3(2x)(y)²+(y)³= 8x³+12x²y+6xy²+y³
10.-(10+a)³= (10)³+3(10)²(a)+3(10)(a)²+(a)³= 1000+300a+30a²+a³
11.-(ab²-d⁵)³= (ab²)³+3(ab²)²(-d⁵)+3(ab²)(-d⁵)²+(d⁵)³ = a³b⁶ - 3a²b⁴d⁵ + 3ab²d¹⁰ + d¹⁵
12.- (10ab-3xy)³= (10ab)³+3(10ab)²(-3xy)+3(10ab)(-3xy)²+(-3xy)³=
1000a³b³ - 900a²b²xy+270abx²y²-27x³y³
13.- (t + 4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³= t³ + 12t² + 48t + 64
14.- (2a – b)³ = (2a)³ -3(2a)²(b)+3(2a)(b)²- b³ =8a³ – 3(4a²)b + 6ab² – b³= 8a³ – 12a²b + 6ab² – b³
15.- (x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8
16.-(1 – 3y)³ = (1)³ – 3(1)²(3y)+3(1)(3y)²- (3y)³ = 1 – 9y + 27y² - 27y³
17.- (2 – a)³ = 2³ – 3(2)²(a) + 3(2)(a)² – a³= 8 – 12a + 6a² - a³
18.- (x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8
19.- (a + 3)³= a³ + 3(a)²(3) + 3(a)(3)² + (3)³= 27 + 9a² + 27a + 27
20.- (3a - 5b)³ = (3a)³-3(3a)²(5b)+3(3a)(5b)²-(5b)³= 27a³ - 135a²b + 225ab² - 125b³
saludos!!!
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