Question

has las siguientes sumas d) [1/2m^3-2/3m^2]+[-2/5m^3+1/6m^2]
xf y las dos últimas xf

Answer 1

[1/2m^3-2/3m^2]+[-2/5m^3+1/6m^2]=

1/2m³ - 2/3m² - 2/5m³ + 1/6m² =
(1/2m³-2/5 m³) + ( 1/6m²-2/3m²)=
(1/2-2/5 ) m³+ ( 1/6-2/3)m²=

1/10m³ - 1/2 m²

Answer 2

Respuesta:

(1/10)m³ – (1/2 )m²

Explicación paso a paso:

d) [(1/2)m³ – (2/3)m²] + [(2/5)m³ + (1/6)m²]

(1/2)m³ – (2/3)m² + (2/5)m³ + (1/6)m²

(1/2 – 2/5)m³ + (1/6 – 2/3)m²

[(5 – 4)/10]m³ + [(1 – 4)/6]m²

(1/10)m³ – (3/6 )m²