Question

2/3×(1/1+1/2)-(4/5-2/3):1/5

Answer 1

Primero se resuelven los  paréntesis
$\frac{2}{3}( \frac{1}{1} + \frac{1}{2} )-( \frac{4}{5} - \frac{2}{3} ): \frac{1}{5}$=
$\frac{2}{3} ( \frac{2+1}{2} )-( \frac{12-10}{15} ): \frac{1}{5} =$
$(\frac{2}{3} \frac{3}{2}) - (\frac{2}{15} : \frac{1}{5})$=
$\frac{6}{6} - \frac{10}{15}$=1-$\frac{2}{3}$=
$\frac{3-2}{3} = \frac{1}{3}$