Question

que volumen de oxigeno medido a 25 grados centigrados y 700 mmhg se nesecitan para quemar 10 litros de butano a la misma temperatura y presion de 1 atm

Answer 1

Ley de los Gases ideales

Datos del butano:
V = 10 L
P = 1 atm
T = 25 ºC + 273 = 298 K
R = 0.082 ( L atm/ mol K)

Datos del oxigeno
V = ?
T = 25 ºC + 273 = 298 K
P = 700 / 760 = 0.921 atm

1. calcular moles de butano

V x P = n x R x T       despejar n (moles de btano)

n =          10 L  x  1  atm
     ``````````````````````````````````
     0.082 (L atm/ mol K) x 298 K

n = 0.41 moles de butano

2.    2C4H10  +   13 O2 →  8 CO2  +  10 H2O

calcular moles de Oxigeno

mol O2  = 0.41 mol C4H1O  x  13 mol O2
                                                   ````````````````
                                                  2 mol C4H10

mol O2 = 2.66

3.   calcular Volumen de Oxigeno

P = 700 / 760 = 0.921  atm
V = ?
T = 25 + 273 = 298 K

V =  2.66  mol x 0.082 ( L atm/mol K) x 298 K
     ```````````````````````````````````````````````````````````
                               0.921 atm

V = 70.5 L  de  oxigeno