Respuestas
Respuesta dada por:
1
Resolver:
1)![20 x^{2} +3x-2=0 20 x^{2} +3x-2=0](https://tex.z-dn.net/?f=20+x%5E%7B2%7D+%2B3x-2%3D0)
Aplicando la formula general:
![x1 = \frac{-b+ \sqrt{b^2-4ac} }{2a} = \frac{-3+ \sqrt{3^2-4.20.(-2)} }{2.20} = \frac{-3+ \sqrt{9+160} }{40} = \frac{-3+ \sqrt{169} }{40} = \frac{-3+13}{40} x1 = \frac{-b+ \sqrt{b^2-4ac} }{2a} = \frac{-3+ \sqrt{3^2-4.20.(-2)} }{2.20} = \frac{-3+ \sqrt{9+160} }{40} = \frac{-3+ \sqrt{169} }{40} = \frac{-3+13}{40}](https://tex.z-dn.net/?f=x1+%3D++%5Cfrac%7B-b%2B+%5Csqrt%7Bb%5E2-4ac%7D+%7D%7B2a%7D+%3D++%5Cfrac%7B-3%2B+%5Csqrt%7B3%5E2-4.20.%28-2%29%7D+%7D%7B2.20%7D+%3D++%5Cfrac%7B-3%2B+%5Csqrt%7B9%2B160%7D+%7D%7B40%7D+%3D++%5Cfrac%7B-3%2B+%5Csqrt%7B169%7D+%7D%7B40%7D+%3D++%5Cfrac%7B-3%2B13%7D%7B40%7D+)
![= \frac{x}{y} \frac{10}{40}= \frac{1}{4} = 0,25 = \frac{x}{y} \frac{10}{40}= \frac{1}{4} = 0,25](https://tex.z-dn.net/?f=%3D+%5Cfrac%7Bx%7D%7By%7D++%5Cfrac%7B10%7D%7B40%7D%3D++%5Cfrac%7B1%7D%7B4%7D+%3D+0%2C25)
[/tex] =![-0,40 -0,40](https://tex.z-dn.net/?f=-0%2C40)
2)
![5z^2=17z+14 =0 5z^2=17z+14 =0](https://tex.z-dn.net/?f=5z%5E2%3D17z%2B14+%3D0)
![x1= \frac{-(-17)+ \sqrt{(-17)^2-4.5.14} }{2.5} = \frac{17+ \sqrt{289-280} }{2.5} = \frac{26}{10} = \frac{13}{5} = 2,6 x1= \frac{-(-17)+ \sqrt{(-17)^2-4.5.14} }{2.5} = \frac{17+ \sqrt{289-280} }{2.5} = \frac{26}{10} = \frac{13}{5} = 2,6](https://tex.z-dn.net/?f=x1%3D+%5Cfrac%7B-%28-17%29%2B+%5Csqrt%7B%28-17%29%5E2-4.5.14%7D+%7D%7B2.5%7D+%3D+%5Cfrac%7B17%2B+%5Csqrt%7B289-280%7D+%7D%7B2.5%7D+%3D++%5Cfrac%7B26%7D%7B10%7D+%3D++%5Cfrac%7B13%7D%7B5%7D+%3D+2%2C6)
![x2= \frac{-(-17)- \sqrt{(-17)^2-4.5.14} }{2.5} = \frac{17- \sqrt{289-280} }{2.5} = \frac{14}{10} = \frac{7}{5} = 1,4 x2= \frac{-(-17)- \sqrt{(-17)^2-4.5.14} }{2.5} = \frac{17- \sqrt{289-280} }{2.5} = \frac{14}{10} = \frac{7}{5} = 1,4](https://tex.z-dn.net/?f=x2%3D+%5Cfrac%7B-%28-17%29-+%5Csqrt%7B%28-17%29%5E2-4.5.14%7D+%7D%7B2.5%7D+%3D+%5Cfrac%7B17-+%5Csqrt%7B289-280%7D+%7D%7B2.5%7D+%3D+%5Cfrac%7B14%7D%7B10%7D+%3D+%5Cfrac%7B7%7D%7B5%7D+%3D+1%2C4)
3)
10w^2-7w-6 = 0
![x1= \frac{-(-7)+ \sqrt{(-7)^2-4.10.(-6)} }{2.10} = \frac{7+ \sqrt{49+240} }{20} = \frac{24}{20} = \frac{6}{5} = 1,20 x1= \frac{-(-7)+ \sqrt{(-7)^2-4.10.(-6)} }{2.10} = \frac{7+ \sqrt{49+240} }{20} = \frac{24}{20} = \frac{6}{5} = 1,20](https://tex.z-dn.net/?f=x1%3D+%5Cfrac%7B-%28-7%29%2B+%5Csqrt%7B%28-7%29%5E2-4.10.%28-6%29%7D+%7D%7B2.10%7D+%3D+%5Cfrac%7B7%2B+%5Csqrt%7B49%2B240%7D+%7D%7B20%7D+%3D+%5Cfrac%7B24%7D%7B20%7D+%3D+%5Cfrac%7B6%7D%7B5%7D+%3D+1%2C20)
![x2= \frac{-(-7)- \sqrt{(-7)^2-4.10.(-6)} }{2.10} = \frac{7- \sqrt{49+240} }{20} = \frac{-10}{20} =- \frac{1}{2} = -0,50 x2= \frac{-(-7)- \sqrt{(-7)^2-4.10.(-6)} }{2.10} = \frac{7- \sqrt{49+240} }{20} = \frac{-10}{20} =- \frac{1}{2} = -0,50](https://tex.z-dn.net/?f=x2%3D+%5Cfrac%7B-%28-7%29-+%5Csqrt%7B%28-7%29%5E2-4.10.%28-6%29%7D+%7D%7B2.10%7D+%3D+%5Cfrac%7B7-+%5Csqrt%7B49%2B240%7D+%7D%7B20%7D+%3D+%5Cfrac%7B-10%7D%7B20%7D+%3D-+%5Cfrac%7B1%7D%7B2%7D+%3D+-0%2C50)
4)
14 x^{2} +17x-6=0
![x1= \frac{-17+ \sqrt{(-17)^2-4.14.(-6)} }{2.14} = \frac{-17+ \sqrt{289+336} }{28} = \frac{8}{28} = 0,29 x1= \frac{-17+ \sqrt{(-17)^2-4.14.(-6)} }{2.14} = \frac{-17+ \sqrt{289+336} }{28} = \frac{8}{28} = 0,29](https://tex.z-dn.net/?f=x1%3D+%5Cfrac%7B-17%2B+%5Csqrt%7B%28-17%29%5E2-4.14.%28-6%29%7D+%7D%7B2.14%7D+%3D+%5Cfrac%7B-17%2B+%5Csqrt%7B289%2B336%7D+%7D%7B28%7D+%3D+%5Cfrac%7B8%7D%7B28%7D+%3D+0%2C29)
![x2= \frac{-17- \sqrt{(-17)^2-4.14.(-6)} }{2.14} = \frac{-17- \sqrt{289+336} }{28} = -\frac{42}{28} = -1,50 x2= \frac{-17- \sqrt{(-17)^2-4.14.(-6)} }{2.14} = \frac{-17- \sqrt{289+336} }{28} = -\frac{42}{28} = -1,50](https://tex.z-dn.net/?f=x2%3D+%5Cfrac%7B-17-+%5Csqrt%7B%28-17%29%5E2-4.14.%28-6%29%7D+%7D%7B2.14%7D+%3D+%5Cfrac%7B-17-+%5Csqrt%7B289%2B336%7D+%7D%7B28%7D+%3D+-%5Cfrac%7B42%7D%7B28%7D+%3D+-1%2C50)
1)
Aplicando la formula general:
2)
3)
10w^2-7w-6 = 0
4)
14 x^{2} +17x-6=0
Preguntas similares
hace 6 años
hace 9 años
hace 9 años
hace 9 años
hace 9 años