Question

9+3×{32÷8+4×[2×(4÷4+1)]}-2

Answer 1

$9+3 \times \left\lbrace32\div8+4\times[2\times(4\div4+1)]\right\rbrace-2= \\ \\ 9+3 \times\left\lbrace4+4 \times [2\times(1+1)]}\right\rbrace-2= \\ \\ 9+3\times4+4 \times [2\times2]}-2= \\ \\ 9+3\times\left\lbrace4+4 \times[4]\right\rbrace-2= \\ \\ 9+3\times16+4-2= \\ \\ 9+3\times 20-2= \\ \\ 9+60-2= \\ \\ 69-2= \\ \\ = \boxed{ \boxed{ \textbf{67}}}$

Saludos y Suerte!!!!!!!

Answer 2

Respuesta:

9 + 3 . { 32 : 8 + 4 . [ 2 . (4 : 4 + 1) ] } - 2 =  

9 + 3 . {32 : 8 + 4  . [ 2 . (1 + 1 ) ] } - 2 =  

9 + 3 . { 32 : 8 + 4 . [ 2 . 2 ] } - 2 =  

9 + 3 . { 32 : 8 + 4 . 4 } - 2 =

9 + 3 . { 4 + 16 } - 2 =  

9 + 3 . 20 - 2 =  

9 + 60 - 2 =  

69 - 2 =  

67

Explicación: