Buenas tardes, tengan la gentileza de ayudarme con la solución y procedimiento de estos ejercicios, muchas gracias!!!
Elimina los denominadores y resuelve
a) 2/3x - 1/5= √6
b) 9π - 15 = 9/7
c) 3/10X - 2/15 = -4/5
Respuestas
Respuesta dada por:
145
Buenas tardes, tengan la gentileza de ayudarme con la solución y procedimiento de estos ejercicios, muchas gracias!!!
Elimina los denominadores y resuelve
a) 2/3x - 1/5= √6
b) 9π - 15 = 9/7
c) 3/10X - 2/15 = -4/5
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Resolvemos :
![a) \\ \\ \dfrac{2x}{3}- \dfrac{1}{5} = \sqrt{6} \\ \\ \\
\dfrac{10x-3}{15} = \sqrt{6} \\ \\ \textit{Elevamos ambos miembros al
cuadrado para eliminar la ra\'iz.} \\ \\ \\ 10x - 3 = \sqrt{6} *15 \\
\\ (10x-3)^{2} = ( \sqrt[\not{2}]{6} * 15)^{2} \\ \\ Aplicamos\ binomio\
al\ cuadrado: \\ \\ (a - b)^{2} = a^{2}-2ab+b^{2} \\ \\ 100x^{2}-60x+9
= 6*225 \\ \\ 100x^{2}- 60x+9 = 1350 \\ \\ 100x^{2}-60x - 1341 = 0\\ \\
Aplicamos\ la\ f\'ormula\ general: \\ \\ \boxed{x= \frac{-b\ñ \sqrt{
b^{2}-4ac}}{2a}} a) \\ \\ \dfrac{2x}{3}- \dfrac{1}{5} = \sqrt{6} \\ \\ \\
\dfrac{10x-3}{15} = \sqrt{6} \\ \\ \textit{Elevamos ambos miembros al
cuadrado para eliminar la ra\'iz.} \\ \\ \\ 10x - 3 = \sqrt{6} *15 \\
\\ (10x-3)^{2} = ( \sqrt[\not{2}]{6} * 15)^{2} \\ \\ Aplicamos\ binomio\
al\ cuadrado: \\ \\ (a - b)^{2} = a^{2}-2ab+b^{2} \\ \\ 100x^{2}-60x+9
= 6*225 \\ \\ 100x^{2}- 60x+9 = 1350 \\ \\ 100x^{2}-60x - 1341 = 0\\ \\
Aplicamos\ la\ f\'ormula\ general: \\ \\ \boxed{x= \frac{-b\ñ \sqrt{
b^{2}-4ac}}{2a}}](https://tex.z-dn.net/?f=a%29+%5C%5C+%5C%5C+%5Cdfrac%7B2x%7D%7B3%7D-+%5Cdfrac%7B1%7D%7B5%7D+%3D++%5Csqrt%7B6%7D++%5C%5C+%5C%5C+%5C%5C+%0A%5Cdfrac%7B10x-3%7D%7B15%7D+%3D++%5Csqrt%7B6%7D+%5C%5C+%5C%5C+%5Ctextit%7BElevamos+ambos+miembros+al+%0Acuadrado+para+eliminar+la+ra%5C%27iz.%7D+%5C%5C+%5C%5C+%5C%5C+10x+-+3+%3D++%5Csqrt%7B6%7D+%2A15+%5C%5C+%0A%5C%5C+%2810x-3%29%5E%7B2%7D+%3D+%28+%5Csqrt%5B%5Cnot%7B2%7D%5D%7B6%7D+%2A+15%29%5E%7B2%7D+%5C%5C+%5C%5C+Aplicamos%5C+binomio%5C%0A+al%5C+cuadrado%3A+%5C%5C+%5C%5C+%28a+-+b%29%5E%7B2%7D+%3D+a%5E%7B2%7D-2ab%2Bb%5E%7B2%7D++%5C%5C+%5C%5C+100x%5E%7B2%7D-60x%2B9%0A+%3D+6%2A225+%5C%5C+%5C%5C+100x%5E%7B2%7D-+60x%2B9+%3D+1350+%5C%5C+%5C%5C+100x%5E%7B2%7D-60x+-+1341+%3D+0%5C%5C+%5C%5C%0A+Aplicamos%5C+la%5C+f%5C%27ormula%5C+general%3A+%5C%5C+%5C%5C+%5Cboxed%7Bx%3D+%5Cfrac%7B-b%5C%C3%B1+%5Csqrt%7B+%0Ab%5E%7B2%7D-4ac%7D%7D%7B2a%7D%7D++)
![x = \dfrac{60\ñ \sqrt{(60)^{2}-4(100)(-1341)} }{2(100)} \\ \\ \\ x =\dfrac{60\ñ \sqrt{3600+536\ 400}}{100} \\ \\ \\ x =\dfrac{60\ñ \sqrt{54\ 0000}}{100} \\ \\ \\ x= \dfrac{60\ñ300 \sqrt{6}}{200} \\ \\ Tenemos\ dos\ soluciones: \\ \\ x_{1} = \dfrac{60+300 \sqrt{6}}{100} \\ \\ \\ x_{2} = \dfrac{60-300\sqrt{6}}{100} x = \dfrac{60\ñ \sqrt{(60)^{2}-4(100)(-1341)} }{2(100)} \\ \\ \\ x =\dfrac{60\ñ \sqrt{3600+536\ 400}}{100} \\ \\ \\ x =\dfrac{60\ñ \sqrt{54\ 0000}}{100} \\ \\ \\ x= \dfrac{60\ñ300 \sqrt{6}}{200} \\ \\ Tenemos\ dos\ soluciones: \\ \\ x_{1} = \dfrac{60+300 \sqrt{6}}{100} \\ \\ \\ x_{2} = \dfrac{60-300\sqrt{6}}{100}](https://tex.z-dn.net/?f=x+%3D++%5Cdfrac%7B60%5C%C3%B1+%5Csqrt%7B%2860%29%5E%7B2%7D-4%28100%29%28-1341%29%7D+%7D%7B2%28100%29%7D+%5C%5C+%5C%5C+%5C%5C+x+%3D%5Cdfrac%7B60%5C%C3%B1+%5Csqrt%7B3600%2B536%5C+400%7D%7D%7B100%7D+%5C%5C+%5C%5C+%5C%5C+x+%3D%5Cdfrac%7B60%5C%C3%B1+%5Csqrt%7B54%5C+0000%7D%7D%7B100%7D+%5C%5C+%5C%5C+%5C%5C+x%3D+%5Cdfrac%7B60%5C%C3%B1300+%5Csqrt%7B6%7D%7D%7B200%7D+%5C%5C+%5C%5C+Tenemos%5C+dos%5C+soluciones%3A+%5C%5C+%5C%5C++x_%7B1%7D+%3D++%5Cdfrac%7B60%2B300+%5Csqrt%7B6%7D%7D%7B100%7D+%5C%5C+%5C%5C+%5C%5C++x_%7B2%7D+%3D+%5Cdfrac%7B60-300%5Csqrt%7B6%7D%7D%7B100%7D++++++)
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![b) b)](https://tex.z-dn.net/?f=b%29)
![9\pi -15 = \dfrac{9}{7} \\ \\ \\ 9\pi = \dfrac{9}{7} + 15 \\ \\ \\ 9\pi =\dfrac{9+105}{7} \\ \\ \\ 9\pi = \dfrac{114}{7} \\ \\ 9\pi*7 = 144 \\ \\ 63\pi = 144 \\ \\ \boxed{\pi= \frac{16}{7} } 9\pi -15 = \dfrac{9}{7} \\ \\ \\ 9\pi = \dfrac{9}{7} + 15 \\ \\ \\ 9\pi =\dfrac{9+105}{7} \\ \\ \\ 9\pi = \dfrac{114}{7} \\ \\ 9\pi*7 = 144 \\ \\ 63\pi = 144 \\ \\ \boxed{\pi= \frac{16}{7} }](https://tex.z-dn.net/?f=9%5Cpi+-15+%3D++%5Cdfrac%7B9%7D%7B7%7D+%5C%5C+%5C%5C+%5C%5C+9%5Cpi+%3D+%5Cdfrac%7B9%7D%7B7%7D+%2B+15+%5C%5C+%5C%5C+%5C%5C+9%5Cpi+%3D%5Cdfrac%7B9%2B105%7D%7B7%7D+%5C%5C+%5C%5C+%5C%5C+9%5Cpi+%3D+%5Cdfrac%7B114%7D%7B7%7D+%5C%5C+%5C%5C+9%5Cpi%2A7+%3D+144+%5C%5C+%5C%5C+63%5Cpi+%3D+144+%5C%5C+%5C%5C+%5Cboxed%7B%5Cpi%3D+%5Cfrac%7B16%7D%7B7%7D+%7D)
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![c)\\ \\ \dfrac{3x}{10}- \dfrac{2}{15} = - \dfrac{4}{5} \\ \\ \\ \dfrac{3x}{10}=-\dfrac{4*3}{5*3}+ \dfrac{2}{15} \\ \\ \\ \dfrac{3x}{10}=-\dfrac{12}{15} + \dfrac{2}{15} \\ \\ \\ \dfrac{3x}{10}= \dfrac{-12+2}{15} \\ \\ \\ \dfrac{3x}{\not{10}} =- \dfrac{10}{\not{15}} \\ \\ \\ \dfrac{3x}{2} = - \dfrac{10}{3} \\ \\ \\ 3(3x) = - 10(2) \\ \\ 9x = - 20 \\ \\ \boxed{\boxed{x=- \frac{20}{9} }} c)\\ \\ \dfrac{3x}{10}- \dfrac{2}{15} = - \dfrac{4}{5} \\ \\ \\ \dfrac{3x}{10}=-\dfrac{4*3}{5*3}+ \dfrac{2}{15} \\ \\ \\ \dfrac{3x}{10}=-\dfrac{12}{15} + \dfrac{2}{15} \\ \\ \\ \dfrac{3x}{10}= \dfrac{-12+2}{15} \\ \\ \\ \dfrac{3x}{\not{10}} =- \dfrac{10}{\not{15}} \\ \\ \\ \dfrac{3x}{2} = - \dfrac{10}{3} \\ \\ \\ 3(3x) = - 10(2) \\ \\ 9x = - 20 \\ \\ \boxed{\boxed{x=- \frac{20}{9} }}](https://tex.z-dn.net/?f=c%29%5C%5C+%5C%5C+%5Cdfrac%7B3x%7D%7B10%7D-+%5Cdfrac%7B2%7D%7B15%7D+%3D+-+%5Cdfrac%7B4%7D%7B5%7D+%5C%5C+%5C%5C+%5C%5C+%5Cdfrac%7B3x%7D%7B10%7D%3D-%5Cdfrac%7B4%2A3%7D%7B5%2A3%7D%2B+%5Cdfrac%7B2%7D%7B15%7D+%5C%5C+%5C%5C+%5C%5C+%5Cdfrac%7B3x%7D%7B10%7D%3D-%5Cdfrac%7B12%7D%7B15%7D+%2B+%5Cdfrac%7B2%7D%7B15%7D+%5C%5C+%5C%5C+%5C%5C+%5Cdfrac%7B3x%7D%7B10%7D%3D+%5Cdfrac%7B-12%2B2%7D%7B15%7D+%5C%5C+%5C%5C+%5C%5C+%5Cdfrac%7B3x%7D%7B%5Cnot%7B10%7D%7D+%3D-+%5Cdfrac%7B10%7D%7B%5Cnot%7B15%7D%7D+%5C%5C+%5C%5C+%5C%5C+%5Cdfrac%7B3x%7D%7B2%7D+%3D+-++%5Cdfrac%7B10%7D%7B3%7D++%5C%5C+%5C%5C+%5C%5C+3%283x%29+%3D+-+10%282%29+%5C%5C+%5C%5C+9x+%3D+-+20+%5C%5C+%5C%5C+%5Cboxed%7B%5Cboxed%7Bx%3D-+%5Cfrac%7B20%7D%7B9%7D+%7D%7D++++++)
Elimina los denominadores y resuelve
a) 2/3x - 1/5= √6
b) 9π - 15 = 9/7
c) 3/10X - 2/15 = -4/5
Resolvemos :
lita1489:
alphamale22 falta un ejercicio,podrías ayudarme???
Respuesta dada por:
6
▪Resolución paso a paso:
a) (2/3)x - 1/5 =√36
(2/3)x - 1/5 = 6
mcm=15
10x - 3 = 90
10x = 90 + 3
10x = 93
x = 93/10
x = 9,3
b) 9π - 15 = -(9/7)
mcm=7
63π - 105 = -9
63π = 105 - 9
63π = 96
π = 96/63
π = 32/21
π = 1,52
c) (3/10)x - 2/15 = -4/5
mcm=150
45x - 20 = -120
45x = 20 - 120
45x = -100
x = -100/45
x = -20/9
x = -2,22
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