Question

(1/3 ab+1/9a^2-1/6 b2) - (3/4 b^2- 1/9 ab+ a^2- 3/2 ab) ayudenme

Answer 1

Sofi

Igual anterior
            
                  1/3ab         +  1/9a^2    -  1/6 b2
           (+ 1/9 + 3/2)ab         - a^2    - 3/4b^2
         _________________________________
       =        35/18ab      - 8/9a^2  - 11/12b^2  RESULTADO FINAL

SUMA DE LAS FRACCIONES
       1/9 + 3/2 = (2 + 27)18
                     = 29/18
       1/3 + 29/18 = (6 + 29)/18
                         = 35/18

        1/9 - 1 = 1/9 - 9/9
                  = - 8/9

       - 1/6 - 3/4 = (- 2 - 9)/12
                      = - 11/12

Answer 2

(1/3ab+1/9a^2-1/6b^2)-(3/4b^2-1/9 ab+ a^2- 3/2 ab) 

1/3ab+1/9a^2-1/6b^2-(3/4b^2-29/18ab+a^2)

1/3ab+1/9a^2-1/6b^2-3/4b^2+29/18ab-a^2

35/18ab-8/9a^2-11/12b^2 R//