alguien ayuda a hacer el procedimiento?
Realiza con notación científica los siguientes cambios de unidades: a) 25 km/h → m/s b) 70 dm/min → km/h c) 45 mg/ml → dag/m3 d) 5817 pm → μm e) 3,7 dam → Tm
Respuestas
Respuesta dada por:
3
a) 25 Km/h a m/s
m/s = 25 Km x 1 hora x 1000 m
`````````` `````````` ````````````
1 hora 3600 s 1 Km
m/s = 6.944
b) 70 dm/min a Km/h
Km/h = 70 dm x 60 min x 1 Km
```````````` ```````````` ````````````````
1 min 1 hora 10000 dm
Km/h = 0.42
c) 45 mg/mL a dag/m3
dag/m³ = 45 mg x 1000 mL x 1000 L x 1 dag
`````````` `````````````` ``````````` ``````````````
1 mL 1 L 1 m³ 10000 mg
dag/m³ = 4500
d) 5817 pm a μm
1 μm ------ 1 x 10⁶ pm
x ------ 5817 pm
x = 0.005817 μm
e) 3.7 Dam a Tm
Tm = 3.7 Dam x 1 Tm
`````````````````````
1 x 10⁻¹² Dam
Tm = 3.7 x 10¹²
m/s = 25 Km x 1 hora x 1000 m
`````````` `````````` ````````````
1 hora 3600 s 1 Km
m/s = 6.944
b) 70 dm/min a Km/h
Km/h = 70 dm x 60 min x 1 Km
```````````` ```````````` ````````````````
1 min 1 hora 10000 dm
Km/h = 0.42
c) 45 mg/mL a dag/m3
dag/m³ = 45 mg x 1000 mL x 1000 L x 1 dag
`````````` `````````````` ``````````` ``````````````
1 mL 1 L 1 m³ 10000 mg
dag/m³ = 4500
d) 5817 pm a μm
1 μm ------ 1 x 10⁶ pm
x ------ 5817 pm
x = 0.005817 μm
e) 3.7 Dam a Tm
Tm = 3.7 Dam x 1 Tm
`````````````````````
1 x 10⁻¹² Dam
Tm = 3.7 x 10¹²
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