Question

a) cuantos gramos de NH3 se pueden obtener por la reduccion de 0,2 moles de nitrogeno en exceso de hidrogeno b) cuantos moles de hidrogeno se consumieron c) cuantas moleculas de NH3 se producen

Answer 1

                           N2  +  3 H2  →  2NH3

a) Mm NH3 = 17 g/mol

g NH3 = 0.2 mol N2  x  2 mol NH3  x  17 g NH3
                                    ````````````````     ```````````````
                                      1 mol N2        1 mol NH3

g NH3 = 6.8 g

b) moles de hidrógeno

mol H2 = 0.2 mol N2   x   3 mol H2
                                        ``````````````
                                         1 mol N2

mol H2 = 0.6

1. calcular moles de NH3

moles NH3 = 0.2 mol N2  x  2 mol NH3
                                             ````````````````
                                               1 mol N2

mol NH3 = 0.4

2. calcular moléculas de NH3

       1 mol  ------ 6.022 x 10²³ moléculas NH3
     0.4 mol ------               x

            x = 2.4088  x  10²³ moléculas NH3