Question

4x2+3x-22=0 formula general necesito ayudaaaaaa urgente xf

Answer 1

$4 x^{2} +3x-22 = 0$

$x_{1} = \frac{-3+ \sqrt{3^2-4(4)(-22)} }{2(4)}$

$x_{1} = \frac{-3+ \sqrt{9+352} }{8} = \frac{-3+ \sqrt{361} }{8} = \frac{-3+19}{8} =2$


$x_{2} = \frac{-3- \sqrt{3^2-4(4)(-22)} }{2(4)}= \frac{-3- \sqrt{9+352} }{8} = \frac{-3- \sqrt{361} }{8} = \frac{-3-19}{8} = - \frac{22}{8}= -\frac{11}{2}$

Las raíces son : x₁ = 2 ; x₂ = -11/2